Help with a logic problem

Hi Everyone,

I am writing an indicator based on 2 variables.

The rule is that: Whenever variable1 (take value 0 and 1) turns to 1 from 0. find the very first bar (including this turning bar) that has variable1 =1 and varibale2=100. It is like looking back, and I choose to look back 5 bars.

My approach is below:

I think my approach is correct and the code is quite straight forward. But still it doesn't work correctly. It assign found[k] to the first condition met even though it is 20 bar away from the turning bar. So the condiiton 5 bar look back is ignore, somehow.

Any help is very much appreciated.

SCFX 

for(int i=1;i<limit;i++)
{ 
  if( variable1[i]=1 &&  variable2[i]=100 )  //identify potential correct point
   {  for(int j=i+5;j>=i;j++)                //look back 5 bar
      {  if(variable1[j]=1 && variable1[i+1]=0
            && variable2!=100)               //find turning bar with variable2 not equal to 100. If found such point, start look back below
            
         { for(int k=j+1;k>=i;k++)  //look back to find the first bar satisfy 2 conditions
            {  if(variable1[k]=1 &&  variable2[k]=100)
               {  found[k]=Close[k];
                  i=j;
                  break; //DONE
               }
            }
         }
      if(brk==1) break;  //DONE and find new point 
      }
   }
}