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## Array initialisation

 194 MetaNt 2014.03.23 08:29 #   Wait in `int Mas_i[3][4] = { 0, 1, 2, 3,   10, 11, 12, 13,   20, 21, 22, 23 };` does 3 represent the number of sets, and 4 the number of distinct numbers within the set? {(w,x,y,z) (a,b,c,d) (i,j,k,l)}
 1815 SDC 2014.03.23 09:23 #   Yes that is how it is dimensioned when you fill the array using initialization, 3 sets of 4. hmmm i know its late and am getting tired but still .. if you were to use a loop to fill it ```int myarray[3,4]={0}; for(int i=0; i<4; i++) { myarray[i,0] = i; }``` that would be the first set of 4 right ? But you cant do that, I would fill the array in a loop the other way around, so it would create 4 sets of 3 ... like the [10,2] array for ten tickets ... ok i got to go to bed i cant think about this anymore now lol Edit: the initialization sequence fills the array [0,i] [1,i] [2,i] I had to think about that for a minute lol... so really I am in a bad habit of doing [10,2] I should do [2,10] arrays for ten tickets so it matches the way initialization would do it.
 1815 SDC 2014.03.23 20:03 #   I think there is still something about array initialisation though ... the sequence of initialization is not what I thought it was .. The [10,2] array is a correct way to handle 2 sets of ten corresponding values, for example the ten order tickets with corresponding types for each ticket. The way we might enter them in a loop would be: ```for(i=0; i<10; i++) { MyArray[i,0] = ticket[i]; MyArray[i,1] = type[i]; }``` So all ten tickets are in put in the first dimension, types in the second then run a second loop [i,1] to enter the types But if we were to enter them one at a time in an initialization sequence we would have to do ticket type ticket type ... MyArray[10,2] = {ticket1, type1, ticket2, type2, ticket3, type3 etc ... That is because the initialization sequence is: MyArray[0,0] MyArray[0,1] MyArray[1,0] MyArray[1,1] MyArray[2,0] MyArray[2,1] etc ... I think I was too tired last night to be considering that lol ... Alternatively... You can use the [2,10] array this means the tickets are entered in a for loop the other way around ```for(i=0; i<10; i++) { MyArray[0,i} = ticket[i]; MyArray[1,i] = type[i]; }``` This time the initialization would be ticket ticket ticket ticket etc........ type type type type ....etc the sequence would be MyArray[0,0] MyArray[0,1] MyArray[0,2] MyArray[0,3] etc through [0,9] then MyArray[1,0] MyArray[1,1] MyArray[1,2] etc ....