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## Angled Trendlines

 5 depasqda 2007.10.13 12:11   Hi Eveyone I would like to know if anyone knows how to code an angled trendline. I am wanting to draw an angled trendline from point a to point b then point c etc, After I have coded the angled trendlines then I would like to store the angles from each trendline and put them in an array for later us. If anyone has any pointers that would be great thanks dd similar
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 2644 phy 2007.10.13 17:41 #   Certainly. Angle and slope are synonymous. Draw a line with a slope of 0.618 for example: ```int start(){ string name = "a"; double theSlope= 0.618; int startBar = 39; int runBars = 7; double price = Close[startBar]; double angle; if(ObjectFind(name) != -1) ObjectDelete(name); ObjectCreate(name, OBJ_TREND, 0, Time[startBar], price, Time[startBar-runBars], price + (runBars * theSlope * Point)); angle = MathArctan(theSlope)/ 3.1415965 * 180; Comment("The angle of line "+name+" is "+DoubleToStr(angle, 2)+" degrees"); return(0); }``` By rearranging things a bit, you can find the angle of an arbitrary line, or draw a line at an arbitrary angle. The angle will be "visually" correct only on a squared chart (in chart properties scale fix 1:1). similar
 5 depasqda 2007.10.15 15:49 #   Hi PHY Thanks for your input, had me a lot dd
 597 irusoh1 2007.10.17 20:11 #   There is an object in MT called trendline by angle, if it is any use to you.
 2644 phy 2007.10.17 21:13 #   Trendline by angle is usable on a squared chart only. It is a "visual" angle tied to the monitor, not the chart. A 45 degree Trendline by Angle is a visual 45 degree line on your display. zoom in zoom out or squeeze the vertical price scale, the line stays put at a 45 degree visual angle. Therefore, it has no relation to time or price, unless you happen to know the ratio of pips to time you have on the chart. The only "known" setup is 1:1, and that is useless for higher timeframes. For trading purposes, an angle needs to be defined in terms of price and time, thus sticking it to the chart. In that scenario, a 45 degree line is a slope of 1 unit of price change in 1 uint of time change, with units defined by your imagination or application. similar
 476 bonechair 2007.11.14 09:54 #   phy wrote: Certainly. Angle and slope are synonymous. Draw a line with a slope of 0.618 for example: ```int start(){ string name = "a"; double theSlope= 0.618; int startBar = 39; int runBars = 7; double price = Close[startBar]; double angle; if(ObjectFind(name) != -1) ObjectDelete(name); ObjectCreate(name, OBJ_TREND, 0, Time[startBar], price, Time[startBar-runBars], price + (runBars * theSlope * Point)); angle = MathArctan(theSlope)/ 3.1415965 * 180; Comment("The angle of line "+name+" is "+DoubleToStr(angle, 2)+" degrees"); return(0); }``` By rearranging things a bit, you can find the angle of an arbitrary line, or draw a line at an arbitrary angle. The angle will be "visually" correct only on a squared chart (in chart properties scale fix 1:1). Hi Howdo you get the slope of the line. It says here 0.618 but how do you get that slope off OBJ_TREND?
 2644 phy 2007.11.14 10:07 #   Consult Geometry 101 http://argyll.epsb.ca/lburns/coordinate_geometry_6.3.html
 476 bonechair 2007.11.14 16:43 #   I was hoping for a quicker solution. Does this mean I have to draw a x and y line on the middle of my trendline and then figure out the xy of it? similar
 2644 phy 2007.11.14 20:25 #   The geometry examples use X and Y often for the coordinate system. Q. What is the coordinate system on a chart? A. Time and Price -- X and Y Ponder some more... similar
 476 bonechair 2007.11.14 22:14 #   I did try this before: double theSlope = (price2 - price1)/(Time[0]-Time[n]); Comment(theSlope); Not sure howto put it. Im getting 0 output. similar
 2644 phy 2007.11.14 22:57 #   Use bar count, not clock time